1940 United States presidential election in Wyoming
The 1940 United States presidential election in Wyoming took place on November 5, 1940, as part of the 1940 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.
Wyoming was won by President Franklin D. Roosevelt, running with the 11th Secretary of Agriculture Henry A. Wallace, with 52.82 percent of the popular vote, against American lawyer and corporate executive Wendell Willkie, running with senator Charles L. McNary, with 46.89 percent of the popular vote.
This would be the last occasion Teton County would vote for a Democratic presidential candidate until Bill Clinton carried the county in 1992 – since then it has become a Democratic island in the nation's "reddest" state.Results by county
