1988 United States presidential election in New Hampshire
The 1988 United States presidential election in New Hampshire took place on November 8, 1988, as part of the 1988 United States presidential election, which was held throughout all 50 states and D.C. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president. New Hampshire voted for the Republicannominee, Vice President George H. W. Bush, over the Democratic nominee, Massachusetts GovernorMichael Dukakis, by a landslide margin of 26.16%. Bush took 62.49% of the vote to Dukakis's 36.33%. Compared to the rest of liberalNew England, New Hampshire historically had a strong fiscal conservative streak to its politics, and Bush's played well to the state's anti-tax electorate. This election would prove to be the GOP's high point in New Hampshire, as the state gave Bush his second-strongest win in the nation, behind only Utah. In the following years, the state would drift to the left, on economic issues and especially on social issues. As the Republican Party moved to embrace the Christian right and became increasingly Southern, the GOP would suffer a rapid decline in its fortunes in New Hampshire. Despite the scale of Bush's victory in 1988, the state would be projected to flip to Democrat Bill Clinton as soon as the polls closed, and do so just 4 years later in 1992, and the state has been Democratic-leaning ever since. This was the last election in which a Republican presidential candidate won a majority of the vote in New Hampshire, although his son George W. Bush would eke out a narrow 48–47 plurality in 2000. The state has voted Democratic in every other election since, even in 2016, when it was the second-closest state, behind Michigan., this is the last election in which a Republican has been able to win every county within the state as well as the last time the counties of Cheshire, Grafton, Merrimack and Strafford voted for the Republican presidential candidate.
