1992 United States presidential election in Kansas
The 1992 United States presidential election in Kansas took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president.
Kansas was won by incumbent President George H. W. Bush with 38.88% of the popular vote over Governor Bill Clinton with 33.74%. Businessman Ross Perot finished in third, with 26.99% of the popular vote. Kansas was surprisingly close, likely because Ross Perot split the vote. Had Clinton won in Kansas, it would have been a major upset victory. Clinton ultimately won the national vote, defeating incumbent President Bush and Perot., this is the last election in which Ellis County, Cherokee County, Leavenworth County, Shawnee County, Labette County, and Miami County voted for a Democratic presidential candidate, as well as the last election in which Wabaunsee County, Anderson County, Jefferson County, and Morris County did not support the Republican candidate.
With 26.99% of the popular vote, Kansas would prove to be Perot's fifth strongest state after Maine, Alaska, Utah and Idaho.Results
Results by county
