In the modern, functional-analytic approach to the study of partial differential equations, one does not attempt to solve a given partial differential equation directly, but by using the structure of the vector space of possible solutions, e.g. a Sobolev spaceWk,p. Abstractly, consider two realnormed spacesU and V with their continuous dualspacesU∗ and V∗ respectively. In many applications, U is the space of possible solutions; given some partial differential operatorΛ : U → V∗ and a specified element f ∈ V∗, the objective is to find a u ∈ U such that However, in the weak formulation, this equation is only required to hold when "tested" against all other possible elements of V. This "testing" is accomplished by means of a bilinear functionB : U × V → R which encodes the differential operator Λ; a weak solution to the problem is to find a u ∈ U such that The achievement of Lax and Milgram in their 1954 result was to specify sufficient conditions for this weak formulation to have a unique solution that depends continuously upon the specified datum f ∈ V∗: it suffices that U = V is a Hilbert space, that B is continuous, and that B is strongly coercive, i.e. for some constant c > 0 and all u ∈ U. For example, in the solution of the Poisson equation on a bounded, open domain Ω ⊂ Rn, the space U could be taken to be the Sobolev space H01 with dual H−1; the former is a subspace of the Lp space V = L2; the bilinear form B associated to −Δ is the L2inner product of the derivatives: Hence, the weak formulation of the Poisson equation, given f ∈ L2, is to find uf such that
Statement of the theorem
In 1971, Babuška provided the following generalization of Lax and Milgram's earlier result, which begins by dispensing with the requirement that U and V be the same space. Let U and V be two real Hilbert spaces and letB : U × V → R be a continuous bilinear functional. Suppose also that B is weakly coercive: for some constant c > 0 and all u ∈ U, and, for all 0 ≠ v ∈ V, Then, for all f ∈ V∗, there exists a unique solution u = uf ∈ U to the weak problem Moreover, the solution depends continuously on the given data: