The function given by is a potential function for the differential equation
Existence of potential functions
In physical applications the functions I and J are usually not only continuous but even continuously differentiable. Schwarz's Theorem then provides us with a necessary criterion for the existence of a potential function. For differential equations defined on simply connected sets the criterion is even sufficient and we get the following theorem: Given a differential equation of the form : with I and J continuously differentiable on a simply connected and open subset D of R2 then a potential function F exists if and only if
Solutions to exact differential equations
Given an exact differential equation defined on some simply connected and open subset D of R2 with potential function F, a differentiable functionf with in D is a solution if and only if there exists real numberc so that For an initial value problem we can locally find a potential function by Solving for y, where c is a real number, we can then construct all solutions.
Second order exact differential equations
The concept of exact differential equations can be extended to second order equations. Consider starting with the first-order exact equation:Since both functions are functions of two variables, implicitly differentiating the multivariate function yieldsExpanding the total derivatives gives thatand thatCombining the terms gives If the equation is exact, then . Additionally, the total derivative of is equal to its implicit ordinary derivative. This leads to the rewritten equation Now, let there be some second-order differential equationIf for exact differential equations, then and where is some arbitrary function only of that was differentiated away to zero upon taking the partial derivative of with respect to. Although the sign on could be positive, it is more intuitive to think of the integral's result as that is missing some original extra function that was partially differentiated to zero. Next, ifthen the term should be a function only of and, since partial differentiation with respect to will hold constant and not produce any derivatives of. In the second order equationonly the term is a term purely of and. Let. If, then Since the total derivative of with respect to is equivalent to the implicit ordinary derivative , then So,and Thus, the second order differential equation is exact only if and only if the below expression is a function solely of. Once is calculated with its arbitrary constant, it is added to to make. If the equation is exact, then we can reduce to the first order exact form which is solvable by the usual method for first-order exact equations.Now, however, in the final implicit solution there will be a term from integration of with respect to twice as well as a, two arbitrary constants as expected from a second-order equation.
Example
Given the differential equationone can always easily check for exactness by examining the term. In this case, both the partial and total derivative of with respect to are, so their sum is, which is exactly the term in front of. With one of the conditions for exactness met, one can calculate that Letting, then So, is indeed a function only of and the second order differential equation is exact. Therefore, and. Reduction to a first-order exact equation yieldsIntegrating with respect to yields where is some arbitrary function of. Differentiating with respect to gives an equation correlating the derivative and the term. So, and the full implicit solution becomesSolving explicitly for yields
Higher order exact differential equations
The concepts of exact differential equations can be extended to any order. Starting with the exact second order equation it was previously shown that equation is defined such that Implicit differentiation of the exact second-order equation times will yield an th order differential equation with new conditions for exactness that can be readily deduced from the form of the equation produced. For example, differentiating the above second-order differential equation once to yield a third-order exact equation gives the following form where and where is a function only of and. Combining all and terms not coming from gives Thus, the three conditions for exactness for a third-order differential equation are: the term must be, the term must be and must be a function solely of.
Example
Consider the nonlinear third-order differential equationIf, then is and which together sum to. Fortunately, this appears in our equation. For the last condition of exactness, which is indeed a function only of. So, the differential equation is exact. Integrating twice yields that. Rewriting the equation as a first-order exact differential equation yields Integrating with respect to gives that. Differentiating with respect to and equating that to the term in front of in the first-order equation gives that and that. The full implicit solution becomes The explicit solution, then, is