Intuitively, Fredholm operators are those operators that are invertible "if finite-dimensional effects are ignored." The formally correct statement follows. A bounded operator T : X → Y between Banach spaces X and Y is Fredholm if and only if it is invertible modulo compact operators, i.e., if there exists a bounded linear operator such that are compact operators on X and Y respectively. If a Fredholm operator is modified slightly, it stays Fredholm and its index remains the same. Formally: The set of Fredholm operators from X to Y is open in the Banach space L of bounded linear operators, equipped with the operator norm, and the index is locally constant. More precisely, if T0 is Fredholm from X to Y, there exists ε > 0 such that every T in L with ||T − T0|| < ε is Fredholm, with the same index as that of T0. When T is Fredholm from X to Y and U Fredholm from Y to Z, then the composition is Fredholm from X to Z and When T is Fredholm, the transpose operator is Fredholm from to, and. When X and Y are Hilbert spaces, the same conclusion holds for the Hermitian adjointT∗. When T is Fredholm and K a compact operator, then T + K is Fredholm. The index of T remains unchanged under such a compact perturbations of T. This follows from the fact that the index i of is an integer defined for every s in , and i is locally constant, hence i = i. Invariance by perturbation is true for larger classes than the class of compact operators. For example, when U is Fredholm and T a strictly singular operator, then T + U is Fredholm with the same index. The class of inessential operators, which properly contains the class of strictly singular operators, is the "perturbation class" for Fredholm operators. This means an operator is inessential if and only if T+U is Fredholm for every Fredholm operator.
Examples
Let be a Hilbert space with an orthonormal basis indexed by the non negative integers. The shift operatorS on H is defined by This operator S is injective and has a closed range of codimension 1, hence S is Fredholm with. The powers,, are Fredholm with index. The adjoint S* is the left shift, The left shift S* is Fredholm with index 1. If H is the classical Hardy space on the unit circle T in the complex plane, then the shift operator with respect to the orthonormal basis of complex exponentials is the multiplication operatorMφ with the function. More generally, let φ be a complex continuous function on T that does not vanish on, and let Tφ denote the Toeplitz operator with symbol φ, equal to multiplication by φ followed by the orthogonal projection : Then Tφ is a Fredholm operator on, with index related to the winding number around 0 of the closed path : the index of Tφ, as defined in this article, is the opposite of this winding number.
For each integer, define to be the restriction of to viewed as a map from into . If for some integer the space is closed and is a Fredholm operator, then is called a B-Fredholm operator. The index of a B-Fredholm operator is defined as the index of the Fredholm operator. It is shown that the index is independent of the integer. B-Fredholm operators were introduced by M. Berkani in 1999 as a generalization of Fredholm operators.
Semi-Fredholm operators
A bounded linear operator T is called semi-Fredholm if its range is closed and at least one of, is finite-dimensional. For a semi-Fredholm operator, the index is defined by
Unbounded operators
One may also define unbounded Fredholm operators. Let X and Y be two Banach spaces.
The closed linear operator is called Fredholm if its domain is dense in, its range is closed, and both kernel and cokernel of T are finite-dimensional.
is called semi-Fredholm if its domain is dense in, its range is closed, and either kernel or cokernel of T is finite-dimensional.
As it was noted above, the range of a closed operator is closed as long as the cokernel is finite-dimensional.