Law of cosines
In trigonometry, the law of cosines relates the lengths of the sides of a triangle to the cosine of one of its angles. Using notation as in Fig. 1, the law of cosines states
where denotes the angle contained between sides of lengths and and opposite the side of length. For the same figure, the other two relations are analogous:
The law of cosines generalizes the Pythagorean theorem, which holds only for right triangles: if the angle is a right angle, then, and thus the law of cosines reduces to the Pythagorean theorem:
The law of cosines is useful for computing the third side of a triangle when two sides and their enclosed angle are known, and in computing the angles of a triangle if all three sides are known.
History
Though the notion of the cosine was not yet developed in his time, Euclid's Elements, dating back to the 3rd century BC, contains an early geometric theorem almost equivalent to the law of cosines. The cases of obtuse triangles and acute triangles are treated separately, in Propositions 12 and 13 of Book 2. Trigonometric functions and algebra being absent in Euclid's time, the statement has a more geometric flavor:Using notation as in Fig. 2, Euclid's statement can be represented by the formula
This formula may be transformed into the law of cosines by noting that. Proposition 13 contains an entirely analogous statement for acute triangles.
Euclid's Elements paved the way for the discovery of law of cosines. In the 15th century, Jamshīd al-Kāshī, a Persian mathematician and astronomer, provided the first explicit statement of the law of cosines in a form suitable for triangulation. He provided accurate trigonometric tables and expressed the theorem in a form suitable for modern usage. As of the 1990s, in France, the law of cosines is still referred to as the Théorème d'Al-Kashi.
The theorem was popularized in the Western world by François Viète in the 16th century. At the beginning of the 19th century, modern algebraic notation allowed the law of cosines to be written in its current symbolic form.
Applications
The theorem is used in triangulation, for solving a triangle or circle, i.e., to find :- the third side of a triangle if one knows two sides and the angle between them:
- the angles of a triangle if one knows the three sides:
- the third side of a triangle if one knows two sides and an angle opposite to one of them :
The third formula shown is the result of solving for a in the quadratic equation. This equation can have 2, 1, or 0 positive solutions corresponding to the number of possible triangles given the data. It will have two positive solutions if, only one positive solution if, and no solution if. These different cases are also explained by the side-side-angle congruence ambiguity.
Proofs
Using the distance formula
Consider a triangle with sides of length,,, where is the measurement of the angle opposite the side of length. This triangle can be placed on the Cartesian coordinate system aligned with edge with origin at C, by plotting the components of the 3 points of the triangle as shown in Fig. 4:By the distance formula,
Squaring both sides and simplifying
An advantage of this proof is that it does not require the consideration of different cases for when the triangle is acute, right, or obtuse.
Using trigonometry
Dropping the perpendicular onto the side through point, an altitude of the triangle, showsMultiplying through by yields
Considering the two other altitudes of the triangle yields
Adding the latter two equations gives
Subtracting the first equation from the last one results in
which simplifies to
This proof uses trigonometry in that it treats the cosines of the various angles as quantities in their own right. It uses the fact that the cosine of an angle expresses the relation between the two sides enclosing that angle in any right triangle. Other proofs are more geometric in that they treat an expression such as merely as a label for the length of a certain line segment.
Many proofs deal with the cases of obtuse and acute angles separately.
Using the Pythagorean theorem
Case of an obtuse angle
proved this theorem by applying the Pythagorean theorem to each of the two right triangles in the figure shown. Using to denote the line segment and for the height, triangle gives usand triangle gives
Expanding the first equation gives
Substituting the second equation into this, the following can be obtained:
This is Euclid's Proposition 12 from Book 2 of the Elements. To transform it into the modern form of the law of cosines, note that
Case of an acute angle
Euclid's proof of his Proposition 13 proceeds along the same lines as his proof of Proposition 12: he applies the Pythagorean theorem to both right triangles formed by dropping the perpendicular onto one of the sides enclosing the angle and uses the binomial theorem to simplify.Another proof in the acute case
Using more trigonometry, the law of cosines can be deduced by using the Pythagorean theorem only once. In fact, by using the right triangle on the left hand side of Fig. 6 it can be shown that:using the trigonometric identity
This proof needs a slight modification if. In this case, the right triangle to which the Pythagorean theorem is applied moves outside the triangle. The only effect this has on the calculation is that the quantity is replaced by As this quantity enters the calculation only through its square, the rest of the proof is unaffected. However, this problem only occurs when is obtuse, and may be avoided by reflecting the triangle about the bisector of.
Referring to Fig. 6 it is worth noting that if the angle opposite side is then:
This is useful for direct calculation of a second angle when two sides and an included angle are given.
Using Ptolemy's theorem
Referring to the diagram, triangle ABC with sides =, = and = is drawn inside its circumcircle as shown. Triangle is constructed congruent to triangle with = and =. Perpendiculars from and meet base at and respectively. Then:Now the law of cosines is rendered by a straightforward application of Ptolemy's theorem to cyclic quadrilateral :
Plainly if angle is right, then is a rectangle and application of Ptolemy's theorem yields the Pythagorean theorem:
By comparing areas
One can also prove the law of cosines by calculating areas. The change of sign as the angle becomes obtuse makes a case distinction necessary.Recall that
- ,, and are the areas of the squares with sides,, and, respectively;
- if is acute, then is the area of the parallelogram with sides and forming an angle of ;
- if is obtuse, and so is negative, then is the area of the parallelogram with sides a and b forming an angle of.
- in pink, the areas, on the left and the areas and on the right;
- in blue, the triangle, on the left and on the right;
- in grey, auxiliary triangles, all congruent to, an equal number both on the left and on the right.
Obtuse case. Figure 7b cuts a hexagon in two different ways into smaller pieces, yielding a proof of the law of cosines in the case that the angle is obtuse. We have
- in pink, the areas,, and on the left and on the right;
- in blue, the triangle twice, on the left, as well as on the right.
The rigorous proof will have to include proofs that various shapes are congruent and therefore have equal area. This will use the theory of congruent triangles.
Using geometry of the circle
Using the geometry of the circle, it is possible to give a more geometric proof than using the Pythagorean theorem alone. Algebraic manipulations are avoided.Case of acute angle, where. Drop the perpendicular from onto =, creating a line segment of length. Duplicate the right triangle to form the isosceles triangle. Construct the circle with center and radius, and its tangent through. The tangent forms a right angle with the radius , so the yellow triangle in Figure 8 is right. Apply the Pythagorean theorem to obtain
Then use the tangent secant theorem, which says that the square on the tangent through a point outside the circle is equal to the product of the two lines segments created by any secant of the circle through. In the present case:, or
Substituting into the previous equation gives the law of cosines:
Note that is the power of the point with respect to the circle. The use of the Pythagorean theorem and the tangent secant theorem can be replaced by a single application of the power of a point theorem.
Case of acute angle, where. Drop the perpendicular from onto =, creating a line segment of length. Duplicate the right triangle to form the isosceles triangle. Construct the circle with center and radius, and a chord through perpendicular to half of which is Apply the Pythagorean theorem to obtain
Now use the chord theorem, which says that if two chords intersect, the product of the two line segments obtained on one chord is equal to the product of the two line segments obtained on the other chord. In the present case: or
Substituting into the previous equation gives the law of cosines:
Note that the power of the point with respect to the circle has the negative value.
Case of obtuse angle. This proof uses the power of a point theorem directly, without the auxiliary triangles obtained by constructing a tangent or a chord. Construct a circle with center and radius , which intersects the secant through and in and. The power of the point with respect to the circle is equal to both and. Therefore,
which is the law of cosines.
Using algebraic measures for line segments the case of obtuse angle and acute angle can be treated simultaneously.
Using the law of sines
By using the law of sines and knowing that the angles of a triangle must sum to 180 degrees, we have the following system of equations :Then, by using the third equation of the system, we obtain a system of two equations in two variables:
where we have used the trigonometric property that the sine of a supplementary angle is equal to the sine of the angle.
Using the identity
leads to
By dividing the whole system by, we have:
Hence, from the first equation of the system, we can obtain
By substituting this expression into the second equation and by using
we can obtain one equation with one variable:
By multiplying by, we can obtain the following equation:
This implies
Recalling the Pythagorean identity, we obtain the law of cosines:
Isosceles case
When, i.e., when the triangle is isosceles with the two sides incident to the angle equal, the law of cosines simplifies significantly. Namely, because, the law of cosines becomesor
Analogue for tetrahedra
An analogous statement begins by taking,,, to be the areas of the four faces of a tetrahedron. Denote the dihedral angles by etc. ThenVersion suited to small angles
When the angle,, is small and the adjacent sides, and, are of similar length, the right hand side of the standard form of the law of cosines can lose a lot of accuracy to numerical loss of significance. In situations where this is an important concern, a mathematically equivalent version of the law of cosines, similar to the haversine formula, can prove useful:In the limit of an infinitesimal angle, the law of cosines degenerates into the circular arc length formula,.
In spherical and hyperbolic geometry
Versions similar to the law of cosines for the Euclidean plane also hold on a unit sphere and in a hyperbolic plane. In spherical geometry, a triangle is defined by three points,, and on the unit sphere, and the arcs of great circles connecting those points. If these great circles make angles,, and with opposite sides,, then the spherical law of cosines asserts that both of the following relationships hold:In hyperbolic geometry, a pair of equations are collectively known as the hyperbolic law of cosines. The first is
where and are the hyperbolic sine and cosine, and the second is
As in Euclidean geometry, one can use the law of cosines to determine the angles,, from the knowledge of the sides,,. In contrast to Euclidean geometry, the reverse is also possible in both non-Euclidean models: the angles,, determine the sides,,.
Unified formula for surfaces of constant curvature
Defining two functions and asallows to unify the formulae for plane, sphere and pseudosphere into:
In this notation is a complex number, representing the surface's radius of curvature.
- For the surface is a sphere of radius, and its constant curvature equals
- for the surface is a pseudosphere of radius with constant curvature
- for : the surface tends to a Euclidean plane, with constant zero curvature.
In the first two cases, and are well-defined over the whole complex plane for all, and retrieving former results is straightforward.
Hence, for a sphere of radius
Likewise, for a pseudosphere of radius
Indeed, and
Verifying the formula in the limit of Euclidean geometry
In the Euclidean plane the appropriate limits for the above equation must be calculated:
and
Applying this to the general formula for a finite yields:
Collecting terms, multiplying with and taking yields the expected formula: