Pocklington primality test
In mathematics, the Pocklington-Lehmer primality test is a primality test devised by Henry Cabourn Pocklington and Derrick Henry Lehmer.
The test uses a partial factorization of to prove that an integer is prime.
It produces a primality certificate to be found with less effort than the Lucas primality test, which requires the full factorization of.
Pocklington criterion
The basic version of the test relies on the Pocklington theorem which is formulated as follows:Let be an integer, and suppose there exist numbers and such that
Then is prime.
Note: Equation is simply a Fermat primality test. If we find any value of, not divisible by, such that equation is false, we may immediately conclude that is not prime. For example, let. With, we find that. This is enough to prove that is not prime.
Proof of this theorem
Suppose is not prime. This means there must be a prime, where that divides.Since,, and since is prime,.
Thus there must exist an integer, a multiplicative inverse of modulo, with the property that
and therefore, by Fermat's little theorem
This implies
This shows that divides the in ', and therefore this ; a contradiction.
Given, if and can be found which satisfy the conditions of the theorem, then is prime. Moreover, the pair constitute a primality certificate which can be quickly verified to satisfy the conditions of the theorem, confirming as prime.
The main difficulty is finding a value of which satisfies. First, it is usually difficult to find a large prime factor of a large number. Second, for many primes, such a does not exist. For example, has no suitable because, and, which violates the inequality in '.
Given, finding is not nearly as difficult. If is prime, then by Fermat's little theorem, any in the interval will satisfy ). This will satisfy as long as ord does not divide. Thus a randomly chosen in the interval has a good chance of working. If is a generator mod, its order is and so the method is guaranteed to work for this choice.
Generalized Pocklington method
A generalized version of Pocklington's theorem is more widely applicable because it does not require finding a single large prime factor of also, it allows a different value of to be used for each known prime factor of.Corollary: Factor as, where and are relatively prime,, the prime factorization of is known, but the factorization of is not necessarily known.
If for each prime factor of there exists an integer so that
then N is prime.
Proof of the corollary:
Let be a prime dividing and let be the maximum power of dividing.
Let be a prime factor of. For the from the corollary set
. This means
and because of also
This means that the order of is
Thus,. The same observation holds for each prime power factor of A,
which implies.
Specifically, this means
If were composite, it would necessarily have a prime factor which is less than or equal to. It has been shown that there is no such factor, which proves that is prime.
The test
The Pocklington–Lehmer primality test follows directly from this corollary.To use this corollary, first find enough factors of so the product of those factors exceeds.
Call this product.
Then let be the remaining, unfactored portion of. It does not matter whether is prime.
We merely need to verify that no prime that divides also divides, that is, that and are relatively prime.
Then, for every prime factor of, find an which fulfills conditions ' and ' of the corollary.
If such s can be found, the Corollary implies that is prime.
According to Koblitz, = 2 often works.
Example
Determine whetheris prime.
First, search for small prime factors of.
We quickly find that
We must determine whether and meet the conditions of the Corollary.
, so.
Therefore, we have factored enough of to apply the Corollary.
We must also verify that.
It does not matter whether is prime.
Finally, for each prime factor of, use trial and error to find an that satisfies ' and '.
For, try.
Raising to this high power can be done efficiently using binary exponentiation:
So, satisfies ' but not '. As we are allowed a different for each, try instead:
So satisfies both ' and '.
For, the second prime factor of, try :
satisfies both ' and '.
This completes the proof that is prime.
The certificate of primality for would consist of the two pairs and.
We have chosen small numbers for this example, but in practice when we start factoring we may get factors that are themselves so large their primality is not obvious. We cannot prove is prime without proving that the factors of are prime as well. In such a case we use the same test recursively on the large factors of, until all of the primes are below a reasonable threshold.
In our example, we can say with certainty that 2 and 3 are prime, and thus we have proved our result. The primality certificate is the list of pairs, which can be quickly checked in the corollary.
If our example had included large prime factors, the certificate would be more complicated. It would first consist of our initial round of s which correspond to the 'prime' factors of ; Next, for each factor of where primality was uncertain, we would have more, and so on for factors of these factors until we reach factors of which primality is certain. This can continue for many layers if the initial prime is large, but the important point is that a certificate can be produced, containing at each level the prime to be tested, and the corresponding s, which can easily be verified.
Extensions and variants
The 1975 paper by Brillhart, Lehmer, and Selfridge gives a proof for what is shown above as the "generalized Pocklington theorem" as Theorem 4 on page 623. Additional theorems are shown which allow less factoring. This includes their Theorem 3 :If is large, it is often difficult to factor enough of to apply the above corollary. Theorem 5 of the Brillhart, Lehmer, and Selfridge paper allows a primality proof when the factored part has reached only. Many additional such theorems are presented that allow one to prove the primality of based on the partial factorization of and.