Sand Hill, Pennsylvania


Sand Hill is a census-designated place in Lebanon County, Pennsylvania, United States. The population was 2,345 at the 2000 census.

Geography

Sand Hill is located at .
According to the United States Census Bureau, the CDP has a total area of, all of it land.

Demographics

As of the census of 2000, there were 2,345 people, 898 households, and 709 families residing in the CDP. The population density was 2,312.5 people per square mile. There were 917 housing units at an average density of 904.3/sq mi. The racial makeup of the CDP was 96.25% White, 0.47% African American, 0.04% Native American, 1.66% Asian, 0.98% from other races, and 0.60% from two or more races. Hispanic or Latino of any race were 2.94% of the population.
There were 898 households, out of which 31.7% had children under the age of 18 living with them, 69.2% were married couples living together, 6.5% had a female householder with no husband present, and 21.0% were non-families. 16.4% of all households were made up of individuals, and 7.3% had someone living alone who was 65 years of age or older. The average household size was 2.61 and the average family size was 2.94.
In the CDP, the population was spread out, with 22.1% under the age of 18, 6.4% from 18 to 24, 29.5% from 25 to 44, 28.5% from 45 to 64, and 13.4% who were 65 years of age or older. The median age was 41 years. For every 100 females, there were 94.9 males. For every 100 females age 18 and over, there were 91.6 males.
The median income for a household in the CDP was $45,125, and the median income for a family was $47,566. Males had a median income of $32,321 versus $23,160 for females. The per capita income for the CDP was $19,386. About 1.3% of families and 1.1% of the population were below the poverty line, including 2.0% of those under age 18 and 2.5% of those age 65 or over.