Schwarz Lemma. Let be the openunit disk in the complex plane centered at the origin and let be a holomorphic map such that and on. Then, and. Moreover, if for some non-zero or, then for some with.
Proof
The proof is a straightforward application of the maximum modulus principle on the function which is holomorphic on the whole of D, including at the origin. Now if Dr = denotes the closed disk of radius r centered at the origin, then the maximum modulus principle implies that, for r < 1, given any z in Dr, there existszr on the boundary of Dr such that As we get. Moreover, suppose that |f| = |z| for some non-zero z in D, or |f′| = 1. Then, |g| = 1 at some point of D. So by the maximum modulus principle, g is equal to a constant a such that |a| = 1. Therefore, f = az, as desired.
Schwarz–Pick theorem
A variant of the Schwarz lemma, known as the Schwarz-Pick theorem, characterizes the analytic automorphisms of the unit disc, i.e. bijective holomorphic mappings of the unit disc to itself: Let f : D → D be holomorphic. Then, for all z1, z2 ∈ D, and, for all z ∈ D, The expression is the distance of the points z1, z2 in the Poincaré metric, i.e. the metric in the Poincaré disc model for hyperbolic geometry in dimension two. The Schwarz-Pick theorem then essentially states that a holomorphic map of the unit disk into itself decreases the distance of points in the Poincaré metric. If equality holds throughout in one of the two inequalities above, then f must be an analytic automorphism of the unit disc, given by a Möbius transformation mapping the unit disc to itself. An analogous statement on the upper half-planeH can be made as follows:
Let f : H → H be holomorphic. Then, for all z1, z2 ∈ H,
This is an easy consequence of the Schwarz-Pick theorem mentioned above: One just needs to remember that the Cayley transformW = / maps the upper half-plane H conformally onto the unit disc D. Then, the map W o f o W−1 is a holomorphic map from D onto D. Using the Schwarz-Pick theorem on this map, and finally simplifying the results by using the formula for W, we get the desired result. Also, for all z ∈ H, If equality holds for either the one or the other expressions, then f must be a Möbius transformation with real coefficients. That is, if equality holds, then with a, b, c, d ∈ R, and ad − bc > 0.
Proof of Schwarz–Pick theorem
The proof of the Schwarz-Pick theorem follows from Schwarz's lemma and the fact that a Möbius transformation of the form maps the unit circle to itself. Fix z1 and define the Möbius transformations Since M = 0 and the Möbius transformation is invertible, the composition φ maps 0 to 0 and the unit disk is mapped into itself. Thus we can apply Schwarz's lemma, which is to say Now calling z2 = M−1 yields the desired conclusion To prove the second part of the theorem, we rearrange the left-hand side into the difference quotient and let z2 tend to z1.