Seconsett Island, Massachusetts


Seconsett Island is a census-designated place in the town of Mashpee in Barnstable County, Massachusetts, United States. The population was 100 at the 2010 census.

Geography

Seconsett Island is located in the southwest part of the town of Mashpee at . It is bounded by the town of Falmouth to the northwest, by Hamblin Pond to the northeast, by the Little River to the southeast, and by Waquoit Bay to the southwest. The only road access is via Meadow Neck Road from Falmouth.
According to the United States Census Bureau, the CDP has a total area of, of which, or 4.53%, is water.

Demographics

At the 2000 census there were 81 people, 43 households, and 23 families in the CDP. The population density was 284.3/km². There were 141 housing units at an average density of 494.9/km². The racial makeup of the CDP was 100.00% White.
Of the 43 households 9.3% had children under the age of 18 living with them, 39.5% were married couples living together, 9.3% had a female householder with no husband present, and 46.5% were non-families. 34.9% of households were one person and 25.6% were one person aged 65 or older. The average household size was 1.88 and the average family size was 2.39.
The age distribution was 13.6% under the age of 18, 3.7% from 18 to 24, 19.8% from 25 to 44, 29.6% from 45 to 64, and 33.3% 65 or older. The median age was 50 years. For every 100 females, there were 80.0 males. For every 100 females age 18 and over, there were 94.4 males.
The median income for a household on the CDP was $17,250, and the median family income is $0. Males had a median income of $21,250 versus $16,250 for females. The per capita income for the CDP was $15,833. None of the population was below the poverty line.