If is a nonnegative random variable and, then the probability that is at least is at most the expectation of divided by : Let ; then we can rewrite the previous inequality as In the language of measure theory, Markov's inequality states that if is a measure space, a measurable extended real-valued function, and, then This measure-theoretic definition is sometimes referred to as Chebyshev's inequality.
If is a monotonically increasing nonnegative function for the nonnegative reals, is a random variable,, and, then An immediate corollary, using higher moments of supported on values larger than 0, is
Proofs
We separate the case in which the measure space is a probability space from the more general case because the probability case is more accessible for the general reader.
Intuitive
where is larger than 0 as r.v is non-negative and is larger than because the conditional expectation only takes into account of values larger than which r.v can take. Hence intuitively, which directly leads to.
Proof in the language of probability theory
Method 1: From the definition of expectation: However, X is a non-negative random variable thus, From this we can derive, From here, dividing through by allows us to see that Method 2: For any event, let be the indicator random variable of, that is, if occurs and otherwise. Using this notation, we have if the event occurs, and if. Then, given, which is clear if we consider the two possible values of. If, then, and so. Otherwise, we have, for which and so. Since is a monotonically increasing function, taking expectation of both sides of an inequality cannot reverse it. Therefore, Now, using linearity of expectations, the left side of this inequality is the same as Thus we have and since a > 0, we can divide both sides by a.
In the language of measure theory
We may assume that the function is non-negative, since only its absolute value enters in the equation. Now, consider the real-valued function s on X given by Then. By the definition of the Lebesgue integral and since, both sides can be divided by, obtaining
Corollaries
Chebyshev's inequality
uses the variance to bound the probability that a random variable deviates far from the mean. Specifically, for any. Here is the variance of X, defined as: Chebyshev's inequality follows from Markov's inequality by considering the random variable and the constant for which Markov's inequality reads This argument can be summarized :
Other corollaries
The "monotonic" result can be demonstrated by:
:
:
The result that, for a nonnegative random variable, the quantile function of satisfies:
:
:the proof using
:
:
Let be a self-adjoint matrix-valued random variable and. Then
:
:can be shown in a similar manner.
Examples
Assuming no income is negative, Markov's inequality shows that no more than 1/5 of the population can have more than 5 times the average income.